Python Babylonian Method – SQRT()

Python implementation of Babylonian Method – method to calculate square root of positive numbers.

IN
3
0.0000000001
OUT
sqrt( 3.0 ) =  0.3
sqrt( 3.0 ) =  5.15
sqrt( 3.0 ) =  2.86626213592233
sqrt( 3.0 ) =  1.956460731776899
sqrt( 3.0 ) =  1.74492093914502
sqrt( 3.0 ) =  1.7320982711195376
sqrt( 3.0 ) =  1.7320508082191837

# © 2018 TheFlyingKeyboard and released under MIT License 
# theflyingkeyboard.net

number = float(input("Enter number to square root: ")) 
precision = float(input("Enter precision of method: "))

if (number < 0):
  print("number must be >= 0")
elif (number == 0): 
  print("sqrt(0) = 0")
else:
  x = number / 10;
  y = number / x;

  counter = 0
  while (x - y > precision or counter <= 1):
    print("sqrt(", number, ") = ", x)
    
    x = (x + y) / 2
    y = number / x

    counter += 1