Simple exercises about creating truth tables of logic gates schemes.
Exercise: Create truth tables for the following logic gates schemes.
Scheme: Easy I-1
Hint: Scheme Equation
Y = P0 NAND B = (NOT A) NAND B
Solution
Scheme: Easy I-1 Truth Table
| A | B | P0 (NOT A) | Y (P0 NAND B) |
|---|---|---|---|
| 0 | 0 | 1 | 1 |
| 0 | 1 | 1 | 0 |
| 1 | 0 | 0 | 1 |
| 1 | 1 | 0 | 1 |
Scheme: Easy I-2
Hint: Scheme Equation
Y = P0 XOR P1 = (NOT A) XOR (NOT P0) = (NOT A) XOR (NOT(NOT A))= (NOT A) XOR A
Solution
Scheme: Easy I-2 Truth Table
| A | P0 (NOT A) | P1 (NOT P0) | Y (P0 XOR P1) |
|---|---|---|---|
| 0 | 1 | 0 | 1 |
| 1 | 0 | 1 | 1 |
Scheme: Easy I-3
Hint: Scheme Equation
Y = P0 AND B = (A OR B) AND B
Solution
Scheme: Easy I-3 Truth Table
| A | B | P0 (A OR B) | Y (P0 AND B) |
|---|---|---|---|
| 0 | 0 | 0 | 0 |
| 0 | 1 | 1 | 1 |
| 1 | 0 | 1 | 0 |
| 1 | 1 | 1 | 1 |
Scheme: Easy I-4
Hint: Scheme Equation
Y = P0 AND B = (A NOR A) AND B
Solution
Scheme: Easy I-4 Truth Table
| A | B | PO (A NOR A) | Y (P0 AND B) |
|---|---|---|---|
| 0 | 0 | 1 | 0 |
| 0 | 1 | 1 | 1 |
| 1 | 0 | 0 | 0 |
| 1 | 1 | 0 | 0 |
Scheme: Easy I-5
Hint: Scheme Equation
Y = P1 OR B = (P0 XNOR B) OR B = ((NOT A) XNOR B) OR B
Solution
Scheme: Easy I-5 Truth Table
| A | B | P0 (NOT A) | P1 (P0 XNOR B) | Y (P1 OR B) |
|---|---|---|---|---|
| 0 | 0 | 1 | 0 | 0 |
| 0 | 1 | 1 | 1 | 1 |
| 1 | 0 | 0 | 1 | 1 |
| 1 | 1 | 0 | 0 | 1 |
Logic Gates Exercises: Easy I